Asta e fune
One end of a uniform beam weighing 30N and 1
m long is attached to a wall with a hinge. The other end is supported by a
wire. Find the tension of the rope. What is the action on the wall?
A+T+W=0 (somma vettoriale)
r×W+2r×T=0 (polo
in O)
Momento del peso = L m g
sin 60°/2
Momento tensione
fune = LT sin 30°
L m g sqrt(3) / 4 = L T /2
T = 2mg/sqrt(3)
A_x= T cos
60° = mg
; A_y= mg-T
sin60°=mg-mg/sqrt(3)
